Pack: Who Wants to be a Data Miner?

Description:

At the RComm 2010 (www.rcomm2010.org), an unusual competition was held. Titled "Who Wants to Be a Data Miner", three challenges were issued to the participants of the conference. In all challenges, participants had to design RapidMiner processes as quickly as possible. This is the winning process of Challenge 1: "99 bottles of beer" by Sebastian Land. This was the task:

Design a process that produces an example set the rows of which form the lyrics of the well-known song "99 bottles of beer". To those who do not know the lyrics, here they are:

99 bottles of beer on the wall, 99 bottles of beer. Take one down and pass it around, 98 bottles of beer on the wall.

98 bottles of beer on the wall, 98 bottles of beer. Take one down and pass it around, 97 bottles of beer on the wall.

...

Description:

This workflow creates the input for the RCOMM 2010 Challenge 2. The solution and description are in workflow "RCOMM Challenge 2: Broken Iris"

Description:

At the RComm 2010 (www.rcomm2010.org), an unusual competition was held. Titled "Who Wants to Be a Data Miner", three challenges were issued to the participants of the conference. In all challenges, participants had to design RapidMiner processes as quickly as possible. This is the winning process of Challenge 2: "Broken Iris" by Nico Piatkowski. This was the task:

You are given a decision tree model (M) designed on the well-known Iris data set and unlabelled data (U) on which the model is to be applied. Unfortunately, the unlabelled data set misses one of the four original attributes (a4), so the model is not immediately applicable. Even worse, you also cannot recreate the model, since in last night's database crash the label column of the original labelled data set (L) was lost. However, this example set contains all four columns. The task is: Given M, U, and L, find a way to apply M to U and convince the audience that this does something useful. (The audience does not accept just re-creating the missing column and filling it with constant or random values.)

The solution uses L to create a regression model that predicts a4 from a1, a2, and a3 and uses this to add an attribute a4 to U. Then, M can be applied to U.

myExperiment workflow "RCOMM Challenge 2: Broken Iris (Preparation)" creates the original input M, U, and T from RapidMiner's Iris sample.

Description:

At the RComm 2010 (www.rcomm2010.org), an unusual competition was held. Titled "Who Wants to Be a Data Miner", three challenges were issued to the participants of the conference. In all challenges, participants had to design RapidMiner processes as quickly as possible. This is the winning process of Challenge 2: "Fibonacci Numbers" by Matko Bošnjak. This was the task:

The n-th Fibonacci number is F(n)=F(n-1)+F(n-2), and F(0)=0, F(1)=1. Create a process that creates an example set with F(n) rows where n can be defined as a macro of the process.

This solution does even more than the intended result: It creates an example set where row i contains F(i).

Description:

At the RComm 2010 (www.rcomm2010.org), an unusual competition was held. Titled "Who Wants to Be a Data Miner", three challenges were issued to the participants of the conference. In all challenges, participants had to design RapidMiner processes as quickly as possible. This is the original solution I had in mind for Challenge 2: "Fibonacci Numbers". It defines a macro n, recurses by applying itself using an "Embed Process" operator on n-1 and n-2, appends the results (so the length is F(n-1)+F(n-2)) and uses a "Branch" operator to stop the recursion. The live solution from the challenge is in workflow "RCOMM Challenge 3: Fibonacci Numbers (Live solution)".

Description:

This is a solution for Challenge 1 of the a live data mining process design competition "Who Wants to be a Data Miner" held at RCOMM 2011 in Dublin.

As you certainly know, Balbo Baggins is the common ancestor of Balbo and Frodo Baggins. The file opened by the operator "Open Ancestor" contains a table with details about parentship in the Baggins family (insert a breakpoint after read CSV). Each example contains a parent and a child. Of course, the same parent can be contained multiple times in the data set. The task of Challenge 1 was to find all descendants (and their their respective levels) from Balbo.

This solution achieves this goal by starting with an example set with a single row (Balbo) and joining the parentship table. This yields all children of Balbo. Repeating this, all grandchildren are found. The process uses a loop to iterate down to level 6 (which is empty because no more information is provided for this level). Bilbo and Frodo are found on Levels 3 and 4, respectively.

Description:

This is a solution for Challenge 2 of the a live data mining process design competition "Who Wants to be a Data Miner" held at RCOMM 2011 in Dublin.

Those of you who loved "You Don't Know Jack" will remember this task: To tell whether a certain word is the name of a vodka or the name of a leader of the Soviet Union. The RapidMiner process was allowed to download data from Wikipedia to make this decision.

One input file contains a list of words for which two attributes "Vodka" or "Leader" with indicator variables are added when running the process. A second utility file contains links to Wikipedia pages on Vodka and leaders of the Soviet Union.

Description:

This is a solution for Challenge 3 of the a live data mining process design competition "Who Wants to be a Data Miner" held at RCOMM 2011 in Dublin.

The task was to generate a dataset that looks like a spiral when viewed in an appropriate plotter.

This process opens a file with three initial data points and subsequently adds more points to the data set in a loop, using macros to extract data values of the predecessors and a "Generate Attributes" operator to add new data points.

To view the result, use a "Scatter Multiple" plot, assign x and y tpo their respective axes, and click on "Points and Lines" to see the spiral.